java service wrapper 在linux下实现jar用服务启动

http://www.diybl.com/　2008-1-25 　网络　点击: 　[ 评论 ]

文章搜索：点击制作chm打包电子书教程

br />#********************************************************************

# Wrapper Windows Properties

#********************************************************************

# Title to use when running as a console

wrapper.console.title=WebAPFWonline Service \\看英文名字

#********************************************************************

# Wrapper Windows NT/2000/XP Service Properties

#********************************************************************

# WARNING - Do not modify any of these properties when an application

# using this configuration file has been installed as a service.

# Please uninstall the service before modifying this section. The

# service can then be reinstalled.

# Name of the service

wrapper.ntservice.name=Servername \\服务名

# Display name of the service

wrapper.ntservice.displayname=Servername Service \\显示的服务名

# Description of the service

wrapper.ntservice.description=Servername Service \\服务描述

# Service dependencies. Add dependencies as needed starting from 1

wrapper.ntservice.dependency.1=

# Mode in which the service is installed. AUTO_START or DEMAND_START

wrapper.ntservice.starttype=AUTO_START //自动启动

# Allow the service to interact with the desktop.

wrapper.ntservice.interactive=false

把ln -s /usr/asc/Servername /etc/init.d
注意( /usr/asc/Servername一定要全路径，否则是一个复制的是个无效文件)

/etc/init.d/Appserver start 这样就可以了测试了

注意：

如果我把wrapper.java.command=%JAVA_HOME%/bin/java

写成系统jdk的全路径 /usr/java/jdk/bin/java

那么 /usr/asc路径下运行 ./Appserver start 是可以的

其他路径下运行 service Appserver start 也可以运行.

估计service这个命令不给他指定JAVA_HOME 可能读不到JAVA_HOME了

这个我也不太清楚

（service Appserver start 会出现
Unable to locate any of the following binaries:
/etc/rc.d/init.d/./wrapper-linux-x86-32
/etc/rc.d/init.d/./wrapper-linux-x86-64
/etc/rc.d/init.d/./wrapper 错误）
或者无法启动jvm（service Appserver console中提示）